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Question
How do i prove this identity?

cotx - tanx = 2cosx * cscx - secx * cscx

Answer
if by this you mean

2cos(x)csc(x) - sec(x)csc(x)

2cos(x)(1/sin(x)) - (1/cos(x))(1/sin(x))

(2cos(x)/sin(x)) - (1/(cos(x)sin(x))

(2cos(x)^2 - 1)/sin(x)

cos(2x)/(sin(x)cos(x))

------------------

cot(x) - tan(x)

(cos(x)/sin(x)) - (sin(x)/cos(x))
(cos(x)^2 - sin(x)^2)/(sin(x)cos(x))
cos(2x)/(sin(x)cos(x))

so


2cos(x)csc(x) - sec(x)csc(x) = cot(x) - tan(x)

more info found at www.math.com/tables/trig/identities.htm

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I can answer questions dealing in mathematics of all kinds except for Physics and Calculus, but i can answer questions in Pre-Calculus and Chemistry. I can also answer questions in Recipes of all kinds. I can find games cheats/walkthroughs, but i can`t find a specific game online or offline. I can also do history and recipes for alcoholic beverages.

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