Advanced Math/Sine graphs.
Expert: Paul Klarreich - 9/20/2007
QuestionHI THERE. I am working on graghing sine fuctions and am struggling yet making it work so far. As I work this problem: y=sin4x - I have determined the period to be pi/2? If this is corect , how do i divide pi/2 by 4 to get my x values?
AnswerQuestioner: MICHAEL
Category: Advanced Math
Private: No
Subject: college math - graghs of sine functions
Question: HI THERE. I am working on graghing sine fuctions and am struggling yet making it work so far. As I work this problem: y=sin4x - I have determined the period to be pi/2? If this is corect , how do i divide pi/2 by 4 to get my x values?
.....................................
Hi, Michael,
Yes, the period is pi/2. Set the 'argument' equal to 2pi and solve the equation. The argument is the object of the sine function, in this case 4x.
Here is my recommendation for graphing a sine or cosine curve:
==== USE COURIER FONT TO VIEW THIS =====
1. If it is a sine curve, draw:
+ /-\
| / \
|/ \
0----+----*----+----+
| \ /
| \ /
+ \-/
That is a CYCLE. Now mark the vertical axis with the amplitude in:
y = A sin (nx). In this case, your A = 1
1+ /-\
| / \
|/ \
0----+----*----+----+
| \ /
| \ /
-1+ \-/
Determine the period, as you did: Set nx = 2pi and solve. In this case, you had the period as pi/2. Mark that at the end of the cycle:
1+ /-\
| / \
|/ \
0----+----*----+----+
| \ /pi/2
| \ /
-1+ \-/
Take half the period and put it in the middle of the cycle.
1+ /-\
| / \
|/ \
0----+----*----+----+
| pi/4 /pi/2
| \ /
-1+ \-/
Take half of THAT and put it as the first quarter of the cycle:
1+ /-\
| / \
|/ \
0----+----*----+----+
| pi/8 pi/4 /pi/2
| \ /
-1+ \-/
Take three times THAT and put it as the third quarter of the cycle:
1+ /-\
| / \
|/ \
0----+----*----+----+
| pi/8 pi/4 3pi/8 pi/2
| \ /
-1+ \-/
That's your graph. If you need more of the graph, you will have to extend this cycle to whatever interval is required.