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Find the sum of two hundred even numbers from 0 to 398.

Hi Angela,

This problem appears to be one of finding the sum of an arithmetic series.

The sequence is 0, 2, 4, 6, ............., 398

This is an arithmetic series with first term of 0 and a last term (200th)of 398.

The formula for the sum of such a series is

S = n/2 [2a + (n-1)d]

where a,d,n are first term, common difference and number of terms respectively.

The sum for your case is therefore

S = 200/2 [2(0) + (200 - 1)2]

= 100 [0 + (199)2]

= 100 (398)

= 39800

I hope you get it. You can always get back to me.

Regards

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