Advanced Math/Volume of odd-shaped swimming pool
Expert: Paul Klarreich - 4/29/2006
QuestionHi,
I have an interesting, and challenging word problem for you that I cannot seem to figure out. Here it goes:
I am trying to find the volume of a swimming pool that is shaped like a perfect right triangle (82ft. x 82ft. x 116ft). The depth by the hypotenuse is zero ft. The depth gradually slopes downward at an equal rate ending with a depth at the right angle of 5ft. I need to find the volume of the pool.
Thank you so much! i appreciate it!
AnswerHi, Lindsay,
Your Question: Hi,
I have an interesting, and challenging word problem for you that I cannot seem to figure out. Here it goes:
I am trying to find the volume of a swimming pool that is shaped like a perfect right triangle (82ft. x 82ft. x 116ft).
>> I assume you mean an isosceles right triangle.
The depth by the hypotenuse is zero ft.
>> Just like mine! Now I know why it says 'no diving at this end.'
The depth gradually slopes downward at an equal rate ending with a depth at the right angle of 5ft. I need to find the volume of the pool.
Thank you so much! i appreciate it!
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What you have is effectively a 'pyramid.' Definition:
A pyramid has a base which is a polygon, and the top vertex is connected to each of the vertices of the base.
The volume of a pyramid, like a cone, which is a pyramid with an infinite number of sides, is 1/3 base * height.
So your 'base' is the triangle, which has area 1/2 82^2, and the height is the 5-foot depth. [Remember, 'base' for a geometric figure has nothing to do with top or bottom.]
So I think your volume is (1/3) (1/2) 82^2 (5)