Expert: Sherman D. - 2/28/2004

Question
I was wondering about finding the zeros of a polynomial with complex coefficents.  Is it even possable to graph on the real plane?

Answer
when given a problem in ax^2 + bx + c = 0 form, use the formula x = (-b ± sqrt(bČ - 4ac))/2a

if it isn't in that form, and you can't put it in that form, you can either send the problems to me and i will see what i can do, or go to www.quickmath.com or www.calculator.com, then difference in the sites, is at calculator.com you have to put them in y = form, but make sure to leave the y = part out, and with quickmath.com, you can put it like y = ax^2 + bx + c or ax^2 + bx + c + 2y = n, n being any value.

As for the complex coefficients, i'm not certain without seeing the problems first, if you can type the problem for me to where i can understand it, then i should be able to help, but i will not be able to know that without the problems themselves.