Expert: Sherman D. - 2/22/2005

Question
How do you compute x^i?
where i is the base of imaginary numbers;  x is any real number;  carat means power.

I have seen Euler's Function  e^ix=...but that does not do it.  Hope you can handle this.  

Answer
x^i = x^(sqrt(-1)) or x^(-sqrt(-1))
or
x^i = x^(sqrt(-1)) or if work the negative side of the sqrt, then 1/(x^(sqrt(-1)))

log(b)x = y    means      b^y = x

log(x)n = i

log(x)n = ±sqrt(-1)

since i don't know what x^i equals, "n" stands for whatever x^i is.

thats about all i can give you, since "i" doesn't have an actual value, i can't really tell you anything more.

if it were i^x, then i could definately help you out.