You are here:

Advanced Math/SO confused..please help

Advertisement

Expert: Sherman D. - 8/7/2006


Question
find the domain of the function:

F(x)=sqrt(2x+3)

and

F(x)=1/x^2-2x-2

Answer
f(x) = sqrt(2x + 3)

since (-2/3) would make this 0, and all negative values would make this complex.

Domain
x >= (-2/3)

------------------------------

f(x) = 1/(x^2 - 2x - 2)

x^2 - 2x - 2 = 0

x = (-b ± sqrt(b^2 - 4ac))/(2a)

x = (-(-2) ± sqrt((-2)^2 - 4(1)(-2)))/(2(1))
x = (2 ± sqrt(4 + 8))/2
x = (2 ± sqrt(12))/2
x = (2 ± sqrt(4 * 3))/2
x = (2 ± 2sqrt(3))/2
x = 1 ± sqrt(3)

Domain

x < 1 - sqrt(3)
1 - sqrt(3) < x < 1 + sqrt(3)
x > 1 + sqrt(3)

for a graph, go to www.calculator.com/calcs/GCalc.html

Advanced Math

All Answers

Answers by Expert:

Ask Experts

Volunteer

Sherman D.

Expertise

I can answer questions dealing in mathematics of all kinds except for Physics and Calculus, but i can answer questions in Pre-Calculus and Chemistry. I can also answer questions in Recipes of all kinds. I can find games cheats/walkthroughs, but i can`t find a specific game online or offline. I can also do history and recipes for alcoholic beverages.

Experience

Mathematics, Recipes, History, and Games.

Education/Credentials
High School graduated. I graduated with honors, and i was in Beta Club for a year and a half.

Awards and Honors
Principle's list and A and B honor roll in high school only.

©2012 About.com, a part of The New York Times Company. All rights reserved.