Expert: Sherman D. - 10/19/2004

Question
Would you mind taking me through the steps to solve the question?
Thanks!

**Two cars started from the same point and traveled on a straight course in opposite directions for exactly 2 hours, at which time they were 208 miles apart. If one car traveled, on average, 8 miles per hour faster than the other car, what was the average speed for each car for the 2-hour trip?**  

Answer
s = d/t

s = 208/2
s = 104

x + (x + 8) = 104

x + x + 8 = 104

2x + 8 = 104

2x = 96

x = 48

x + 8 = 48 + 8 = 56

the answer is 48 mph and 56mph

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Since Speed = distance/time, i just did it like this

x + (x + 8) = 208/2

and i got

x + x + 8 = 104

and you know the rest.

average speed of the 2 cars = (average distance)/(average time)