Expert: Sherman D. - 3/9/2004

Question
You were a great help last time, here are some other problems I need to study for a test, can you please show work and give the answer on each problem. Thanks for your time

a ^ before a number means that that number is an exponent, numbers inbetween two ~ marks mean the numbers are in a radical

solve and Graph

y=4(2x)

y=2(1/2)x

y=-2(3x)

find the following f(x)=3x+8 and g(x)=5-6x

f(x)+g(x)

f(g(x))

g(f(x))

f(x)=(5/6x+15)

f(x)=4x-7

find the inverse

{(0,10)(6,8)(9,2)(-11,5)}

evaluate or simplify each expression

3~216~

(-8)^2/3

16^3/2

32^-1/5

4~81~

2^3/2 times 2^5/2

(3^2/3 times 5^1/3)^3

x^9/2division line
x^1/2

3~x^6y^21~ (not 6y though, 6 is the exponent of x)

solve each equation

~x~=20

~x-6~=13

x^1/2=8

~4x~=12

3(x+5)^213=108

x-2=~x~

~6x+8~-~2x~+52=0

3~2x+1~+4=6

Thank you very much  

Answer
So by these do you mean

y = 4(2x)

y = 2 * (1/2)x

y = -2(3x)

find the following f(x) = 3x + 8 and g(x)= 5 - 6x

f(x) + g(x)

f(g(x))

g(f(x))

f(x) = ((5/6)x + 15) or f(x) = 5/(6x + 15)

f(x) = 4x - 7

find the inverse

{(0,10)(6,8)(9,2)(-11,5)}

evaluate or simplify each expression

3sqrt(216) or cbrt(216)

(-8)^(2/3)

16^(3/2)

32^(-1/5)

4sqrt(81) or 4thrt(81)

(2^(3/2)) * (2^(5/2))

(((3^(2/3)) * (5^(1/3)))^3

(x^9)/2

x^(1/2)

cbrt(x^6 * y^21) or 3sqrt(x^6 * y^21)

solve each equation

sqrt(x) = 20

sqrt(x - 6) = 13

x^(1/2) = 8

sqrt(4x) = 12

3(x + 5)^213 = 108, by the way, ^213 is a realy big exponent, are you sure that is what you meant, or did you mean 3(x + 5)^(2/3) = 108

x - 2 = sqrt(x)

sqrt(6x + 8) - sqrt(2x) + 52 = 0

cbrt(2x + 1) + 4 = 6 or 3sqrt(2x + 1) + 4 = 6

if, then just let me know, and i can answer ALL of your problems.

By the way, cbrt = cube root, sqrt = square root, 4thrt = 4th root, * = multiply. For most i should be able to tell you where to graph, and how to solve about all the problem. Depending if i am understanding or what you right back. Also sorry i didn't send this sooner, but i was busy yesterday/last night, and i have been gone about half the day today.