Expert: Steve Holleran - 5/13/2007

Question
How do I find the integral from 2 to 0 of the square root of 4x-1 dx

Answer
Hi Kevin,

I think the problem here is that the function is undefined on the interval you are noting.

Sqrt(4x - 1) will only be defined where 4x - 1 >= 0, which means 4x >= 1 or x >= 1/4.  Since you are trying to integrate the function on an interval where it is undefined, its not going to go.

Let me know if there's any follow up I can help with.

Steve Holleran