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Question
find dy/dx.

1) ln y=e^ysinx
2) e^2x=sin(x+3y)

Answer
1)

y'/y =( y'sinx + ycosx) e^ysinx

y' = (yy'sinx)(e^ysinx) + (y^2 cosx)(e^ysinx)

y'-(yy'sinx)(e^ysinx)=(y^2 cosx)(e^ysinx)

y'(1-(ysinx)(e^ysinx))=(y^2 cosx)(e^ysinx)

y' = (y^2 cosx)(e^ysinx)/(1-(ysinx)(e^ysinx))

2)

2e^2x = (1+3y')cos(x+3y)

2e^2x - cos(x+3y) = 3y'cos(x+3y)

y' = (2e^2x - cos(x+3y))/3cos(x+3y)

y' = 2e^2x/3cos(x+3y) - 1/3

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