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Question
The question states:
Pat invested a total of $3000. Part of the money yields 10% interest per year, and the rest yields 8% interest per year. If the total yearly interest from this investment is $256, how much did Pat invest at 10% and how much at 8%?
Thanks!
sorry it took so long, i had to ask someone for help to see what i was doing wrong.
x + y = 3000
.10x + .08y = 256
x + y = 3000
10x + 8y = 25600
x + y = 3000
5x + 4y = 12800
x + y = 3000
y = -x + 3000
5x + 4(-x + 3000) = 12800
5x - 4x + 12000 = 12800
x = 800
y = -800 + 3000
y = 2200
ANS : $800 at 10% interest per year and %2200 at 8% interest per year.
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Advanced Math
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Sherman D.
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