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Expert: Sherman D. - 7/12/2005


Question
What kind of solutions does ax^2-bx+c=0 have if b^2-4ac<0?
two real solutions, two complex solutions, one complex
solution, or one real solution?

Answer
If you really did mean to type ax^2 - bx + c = 0 instead of ax^2 + bx + c = 0, then i believe the answer this remains the same, but i am not certain, since the most common equationi is ax^2 + bx + c = 0.

b^2 - 4ac > 0 = 2 real solutions
b^2 - 4ac = 0 = 1 real solution
b^2 - 4ac < 0 = 2 complex solutions

so the answer is 2 complex solutions  

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Sherman D.

Expertise

I can answer questions dealing in mathematics of all kinds except for Physics and Calculus, but i can answer questions in Pre-Calculus and Chemistry. I can also answer questions in Recipes of all kinds. I can find games cheats/walkthroughs, but i can`t find a specific game online or offline. I can also do history and recipes for alcoholic beverages.

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Mathematics, Recipes, History, and Games.

Education/Credentials
High School graduated. I graduated with honors, and i was in Beta Club for a year and a half.

Awards and Honors
Principle's list and A and B honor roll in high school only.

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