Advanced Math/A lottery,playing a calculated guess rather than just a guess
Expert: Ahmed Salami - 11/7/2004
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The U.K.Lottery has 49 numbers we have to choose 6 to win the big prize which makes odds of 13,983,816/1. the lowest possible sum total of six numbers is 21, the highest 279. making 259 different sum totals in all.
So the question is how many combinations are they in each different sum total, I know that the sum total of 150 must hold the most, but how do I find its total combinations?
I'm trying to make the lottery a little bit more controlable and interesting as an alternative to plain guessing
Answer -
Hi bertie,
I'm terribly sorry about the delay.
But i'm afraid i don't really get the question. I'm talking about the different sum total part. I really don't get it. You would do well in writing me back and explaining better.
You'll get a quick response this time.
Regards.
Sorry! Ahmed, I'll try again,
Thanks a lot for replying, but this thing is driving me nuts!
O/k, The lowest possible sum total of 6 numbers must be
1+2+3+4+5+6 = 21 which is just one combination
the highest possible S/T, also holding just one combination must be
44+45+46+47+48+49 = 279 (any 6 from 1 to 49)
From the s/t of 21 to the s/t of 279 there are 259 different s/t's
holding 13,983,816 combinations (279-21 = 258 +1 =259)
Therefore, how many combinations are there if the winning 6 numbers add-up to 150, which also happens to be exactly half way between 21 and 279
(258/2 = 129 + 21 =150, or 279-129 =150)so there must be 129 sum totals on each side of the centre of 150, going from the maximum set of combinations to the minimum on ether side (from 1@21 to max@150? to 1@279)
If my choosen 6 numbers also came to 150, then how close am I to winning the lottery?
To give myself some idea I divided 130 into 13,983,816 for the 150 mark, but this is a straight line graph and must be wrong, anyway it will not help if I wanted say, the sum total of 100 for 6 numbers, which will also have the same amount of combinations as the sum total of 200 etc.,
Hope I hav'nt gone on too long and everything you need is here, don't get too bored will you, and good luck
Thanks again
Kind regards bertie
Must go now and check for this weeks lottery of £18m ,If I have won then you can have a nice holiday on me!!!!:-)bye
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Hi bertie,
I was about sending you a reply, but i just got another idea. I have to take some time to review it.
I'm sorry to take all the time.
Good luck.
Hi Ahmed
It's bertie again, I only asking if there's any progess on my questions, hope everything is O/K with you. kind regards Bertie
Answer -
Hello bertie,
Been long. I have to confess that i completely forgot about making any progress as regards your question when you gave me the time to. But since you've asked again, i knew it was time i did something about it.
I wouldn't lie to you but i didn't seem to find a direct formula that gives the number of combinations for a particular sum total. Using some intrinsic knowledge, i tried formulating the normal distribution, error function in order to get what i could call a good approximation. Anyway, i ended up using the binomial distribution for the modelling but i'll spare you the maths and go straight. As you already know the nature of the problem, the number of combinations for a sum total of 150 is the greatest.
At the end of my manipulations, i got close to a probability of (258C129)/(2^258)for the sum total of 150.
nCr is read 'n combination r'. This amounts to a probability of about 0.0496 which means that there are about 693961 different combinations to obtain a sum total of 150. I'm hoping i could also use this method for other sum totals too.
Well, as usual, i welcome any additional things you have to say. Forgive me for any delay i've made.
As for your other question about me being OK, i'm not and i haven't been. I always believe that a problem shared is already half solved, we could talk if you want to know, maybe you could have a few inspirational words to say. The truth is that i never underestimate anyone.
Most importantly, i hope i have helped you.
Good luck.
Regards.
Hi Ahmed
Very sorry to hear you have some personal problems talk to me as much as you want if it helps then it's the least I can do for all the trouble I've caused. Thanks for trying but I do feel the answer you gave is a little on the high side, because of the simple straight line graph I first made which gave the 150 sum total holding only 126,780 combinations,which I feel, at best is only about 50% out, you could be right I just don't know, but someone told me about a lottery web site in Canada that may help, have yet to give it a try.
Anyway do come back to me and lets see if I can help! True Regards bertie
Answer -
Hi Bertie,
How've you been?
I was just wondering why i haven't heard from you.
Take care.
Hi Ahmed
Sorry for the delay but I've been waiting for you to come back to me because my computer crashed and I lost everything, I mean everything. I thought I was protected but the one year firewall run out and they never notified to renew, so bang it went, My computer installer said it was the worst crash he'd seen, it had to me eh!
Anyway I manage to get the combinations for each of 259 sum totals from a Canadian site (I crashed soon after, strange?) The 150 shows it holds 165,772 combinations, but I still don't know how! Perhaps you might be able to workout a formula from this list.
How are you anyway I think you was having problems the last time I e-mailed, hope it's sorted out bye now because time is about the most inexpensive healer you can find apart from keeping busy and friends.
Regards bertie ( who's scared to punch in a key at the moment, it will pass, I hope!)Sorry I dont know how to format so start at the bottom at the 150 mark and the sum of 21 and 279 = 1 comb
Sum comb's Sum
21 1 279
22 1 278
23 2 277
24 3 276
25 5 275
26 7 274
27 11 273
28 14 272
29 20 271
30 26 270
31 35 269
32 44 268
33 58 267
34 71 266
35 90 265
36 110 264
37 136 263
38 163 262
39 199 261
40 235 260
41 282 259
42 331 258
43 391 257
44 454 256
45 532 255
46 612 254
47 709 253
48 811 252
49 931 251
50 1,057 250
51 1,206 249
52 1,360 248
53 1,540 247
54 1,729 246
55 1,945 245
56 2,172 244
57 2,432 243
58 2,709 242
59 3,009 241
60 3,331 240
61 3,692 239
62 4,070 238
63 4,494 237
64 4,935 236
65 5,426 235
66 5,940 234
67 6,506 233
68 7,079 232
69 7,748 231
70 8,423 230
71 9,163 229
72 9,933 228
73 10,769 227
74 11,637 226
75 12,579 225
76 13,552 224
77 14,603 223
78 15,690 222
79 16,856 221
80 18,059 220
81 19,349 219
82 20,673 218
83 22,087 217
84 23,940 216
85 25,082 215
86 26,663 214
87 28,340 213
88 30,051 212
89 31,860 211
90 33,706 210
91 35,648 209
92 37,625 208
93 39,703 207
94 41,809 206
95 44,016 205
96 46,253 204
97 48,586 203
98 50,944 202
99 53,402 201
100 55,875 200
101 58,446 199
102 61,031 198
103 63,706 197
104 66,388 196
105 69,161 195
106 71,928 194
107 74,781 193
108 77,624 192
109 80,542 191
110 83,440 190
111 86,412 189
112 89,348 188
113 92,340 187
114 95,311 186
115 98,324 185
116 101,285 184
117 104,295 183
118 107,235 182
119 110,215 181
120 113,119 180
121 116,048 179
122 118,889 178
123 121,751 177
124 124,507 176
125 127,274 175
126 129,930 174
127 132,581 173
128 135,109 172
129 137,629 171
130 140,008 170
131 142,370 169
132 144,587 168
133 146,771 167
134 148,800 166
135 150,794 165
136 152,627 164
137 154,397 163
138 156,004 162
139 157,554 161
140 158,923 160
141 160,236 159
142 161,354 158
143 162,410 157
144 163,273 156
145 164,062 155
146 164,654 154
147 165,176 153
148 165,490 152
149 165,732 151
150 165,772 150
AnswerHi Bertie,
Thank you for the reply.
I'm sorry about your computer, hope you've had it sorted out now.
About what i wanted to share with you, i'm not sure it would be convenient on here. If you don't mind, we could talk via email or even instant messaging on yahoo or msn. Just let me know whichever one suits you most even if it is on here.
Thank you for the concern, i really want to share this.
I await your quick response. Take care.
Regards.