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Expert: Steve Holleran - 11/24/2007


Question
I keep getting to the end and then I know I can't take the log of a negative number. Where am I going wrong?
log(2x-1)=log(x+3)+log 4

Answer
Hi Heather,

Well, I am getting the same answer you are, but that doesn't mean you are wrong.  You should get x = -13/2, but it doesn't check, as you said, so to me that means there is no solution to the equation.

An equation with no solution is always a possibility.

Steve

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Steve Holleran

Expertise

I can help with all math questions from basic math to Calculus. Whether it`s consumer questions, or questions from high school or college students, I have probably dealt with it at some time in my career.

Experience

33 years teaching experience in NJ public schools

Education/Credentials
B.S. Mathematics : Wake Forest University 1972 M.S. Mathematics : Monmouth University 1981

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