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Expert: Sherman D. - 7/5/2006


Question
How do you calculate the angles of a scalene right triangle?  The sides are 27", 33.5", 43" with the junction of 27 and 33.5 being the right triangle.

Thanks,


Bob

Answer
sqrt(1851.25) = (1/2)sqrt(7405)

sin(x) = opposite/hypothenuse

sinA = 27/((1/2)sqrt(7405))
sinA = 54/(sqrt(7405))
A = sin^-1(54/(sqrt(7405)))
A = about 38.87°

sinB = (33.5)/((1/2)sqrt(7405))
sinB = 67/(sqrt(7405))
B = sin^-1(67/(sqrt(7405)))
B = about 51.13

If you add A and B together, you will get 90°, which is what Angle B is. And 90 plus 90, equals 180

A = about 38.87°
B = about 51.13°

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Sherman D.

Expertise

I can answer questions dealing in mathematics of all kinds except for Physics and Calculus, but i can answer questions in Pre-Calculus and Chemistry. I can also answer questions in Recipes of all kinds. I can find games cheats/walkthroughs, but i can`t find a specific game online or offline. I can also do history and recipes for alcoholic beverages.

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Mathematics, Recipes, History, and Games.

Education/Credentials
High School graduated. I graduated with honors, and i was in Beta Club for a year and a half.

Awards and Honors
Principle's list and A and B honor roll in high school only.

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