Expert: Ahmed Salami - 6/13/2004

Question
Find two numbers such that the sum of their squares is 47 and the difference of their squares is 7.

Answer
Hi stef,
How about going through it like this.
Let the numbers be x and y, as usual,
x^2 + y^2 = 47
x^2 - y^2 = 7
Adding these equations gives us
2(x^2) = 54
(x^2) = 27
x = sqrt 27
x = sqrt9.sqrt3
x = 3(sqrt3)
Going back to the first equation,with (x^2) = 27
27 + y^2 = 47
y^2 = 20
y = sqrt 20
y = sqrt4.sqrt5
y = (sqrt5)
I believe these should be fine.
Regards.