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Question
arrange the numbers 1 through 15, placing them in boxes so that the two numbers in any adjacent box have a sum that is a square number. Do this in a way that the number in the box at the left is less than the number in the box at the right. The boxes are horizontally beside each other.
Please help.
Hi Xia,
Perhaps I am misunderstanding the question, but if the boxes are in a single row, and you have the all numbers from 1 to 15, the only way that you can place them such that the number at the left is less than the number at the right is if the number are in order. But if that is the case, the sums are not square numbers. So I don't think that the question can be solved, unless I missed something.
I hope this helps,
Jack
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Answers by Expert:
Jack Cheng
Expertise
I can answer most questions in Math up to single-variable Calculus, including infinite series. I like to think very much, so questions with a lot of twists and turns are highly welcomed! Mathematical questions related to computer science are also highly welcomed! I can also answer some basic questions in discrete mathematics (logics, sets, some algorithms, basic number theory). I am also studying physics (mechanics in particluar), so I am willing to answer some questions relating to it.
Experience
Majoring in Mathematics.
Education/Credentials
I am sophomore/junior status in college working towards bachelor's degrees in Computer Science and Mathematics.
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