AllExperts > Aerospace/Aviation 
Search      
Aerospace/Aviation
Volunteer
Answers to thousands of questions
 Home · More Aerospace/Aviation Questions · Answer Library  · Encyclopedia ·
More Aerospace/Aviation Answers
Question Library

Ask a question about Aerospace/Aviation
Volunteer
Experts of the Month
Expert Login

Awards

About Us
Tell friends
Link to Us
Disclaimer

 
 
 
 
About Mark Janus
Expertise
I can answer questions regarding aerodynamics, fluid flow, and computational simulations.

Experience
turbomachinery flow analysis, computational fluid dynamics

Organizations
Mississippi State University

AIAA

SIAM

Education/Credentials
Ph.D. in Aerospace Engineering

 
   

You are here:  Experts > Science > Aerospace/Aviation > Aerospace/Aviation > hypothetical flight scenario question...

Aerospace/Aviation - hypothetical flight scenario question...


Expert: Mark Janus - 7/15/2009

Question
This is a question my cousin came up with... I am thinking about how to solve it...

---

If a jet (size - 777-747, etc.- is your choice but let me know which one you choose and the Concord is excluded from this scenario) were to leave JFK while the sun is exactly half way on the western horizon, how fast would its speed have to be to get to LA, keeping the sun in the exact position, and the second part is: how long would it take?  I know rotational speed of the earth factors into it but beyond that.......

----

I know that the earth is 37,500 miles in circumference approximately, and that an average jet flies at about 550-MilesPerHour. I calculated that the rotational velocity of the earth would be about 1,562.5 MilesPerHour at 37,500miles devided by 24hours.

To maintain the Sun at the horizon during flight, you would have to fly counterclockwise to earths rotation at 1,562.5 miles per hour, I am assuming, (I hope this is correct), roughly the speed of the former concorde. Is this right?...

..If not, can you please explain, to help understand where I went wrong?

Answer
What you've calculated sounds reasonable, except the circumference of the Earth is about 25,000 miles at the equator....  so you are off in your calcs by a factor of 1.5   this is all assuming you are at the equator...  it would be much easier to do at higher latitudes (it would require much less speed)...  

mj

Add to this Answer   Ask a Question


 
User Agreement | Privacy Policy | Kids' Privacy Policy | Help
Copyright  © 2008 About, Inc. AllExperts, AllExperts.com, and About.com are registered trademarks of About, Inc. All rights reserved.