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Hi, can't figure out how to solve for X.
a(x+c)=bx+d thanks
Hello Jen,
a(x+c)=bx+d, now distribute...
ax+ac=bx+d, subtract bx from both sides to get
ax-bx+ac=d, now subtract ac from both sides
ax-bx=d-ac, now facot 'x' from the left side
x(a-b)=d-ac, now divide by 'a-c'
Thus, x=(d-ac)/(a-b)
OK?
Abe
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Answers by Expert:
Abe Mantell
Expertise
Hello, I am a college professor of mathematics and regularly teach all levels from elementary mathematics through differential equations, and would be happy to assist anyone with such questions!
Experience
Over 15 years teaching at the college level.
Organizations
NCTM, NYSMATYC, AMATYC, MAA, NYSUT, AFT.
Education/Credentials
B.S. in Mathematics from Rensselaer Polytechnic Institute
M.S. (and A.B.D.) in Applied Mathematics from SUNY @ Stony Brook
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