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Algebra/slope intercept corrections please

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Question
what is the slope intercept form of the equation of a line that passes through (4,-6) and (3,2)

-what is the slope intercept form of the equation of a line that passes through (2/3) and (6,4)

-given is f(x)x^2-4x+5/x+7 find(-2).


-how do u graph this equation -3x+2y=-6  and  2x+y=3

-please help me to solve...2x-8=4(3x+7)

-to solve and graph 3(2x+8)<48

Answer
1. y = -8x+26
2. y = (1/4)x+5/2 or 4y = x+10
3. f(-2) = 17/5
4. Those are both straight lines which only require two points to plot.  Just put in a value for x, calculate y, and plot (x,y).  Repeat for a second point.  
5. 2x-8 = 12x+28 so -10x = 36 and x = -18/5
6. x < 4, draw a vertical line at x=4 and x<4 is any point to the left of the line.

Algebra

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