Algebra/Algebra

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Question
I have one bucket and 2 faucets.  One faucet can fill the bucket alone in 6 minutes.  The other faucet can fill the bucket alone in 4 minutes.  How many seconds will it take to fill the bucket with both faucets on?

Answer
Hello Stacey,

Since work = (rate of work)x (time), we get:
The rate of work for the first faucet is 1 bucket in 6 minutes, or
1/6 of a bucket/minute.
For the second faucet, it is 1/4 of a bucket/minute.

Together, the rate is 1/6 + 1/4 bucket/minute = 10/24 = 5/12 bucket/min.

Now let t=the time to fill the bucket with both faucets on.  Thus,
(5/12)t=1 (i.e. 1 bucket)...solving for t gives t=12/5 minutes
or 2.4 minutes = 2 minutes 24 seconds = 144 seconds.

OK?  I hope this helps!

TTYL, Abe

Algebra

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Abe Mantell

Expertise

Hello, I am a college professor of mathematics and regularly teach all levels from elementary mathematics through differential equations, and would be happy to assist anyone with such questions!

Experience

Over 15 years teaching at the college level.

Organizations
NCTM, NYSMATYC, AMATYC, MAA, NYSUT, AFT.

Education/Credentials
B.S. in Mathematics from Rensselaer Polytechnic Institute
M.S. (and A.B.D.) in Applied Mathematics from SUNY @ Stony Brook

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