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Algebra/Algebra Distance Word Problems

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Question
Hello

This is an example of the type of problem I'm having trouble with. I'm looking for more than just the answer though. I need to understand the theory behind the problem so that I can solve other problems of this type and similar types...
A man drove from home at an average speed of 30mph to an airport. He then boarded a helicopter and flew to the corporate office at an average speed of 60mph. The entire distance was 150 miles. The entire trip took 3 hours. Find the distance from the airport to the corporate office.

I need to get the answer using 1 equation and 1 variable.

What I've figured out so far is...

 Distance from home to airport = 150 - D
Distance from airport to office = D
       Distance total distance = 150 miles [given]
    Speed from home to airport = 30 mph [given]
  Speed from airport to office = 60mph [give]
average speed from home-office = 50 [150 divided by 3]
    Time from house to airport = (150 - D) divided by 30
   Time from airport to office = D divided by 60
        Time total travel time = 3 hours [given]

Unfortunately I have no idea how to set up the actual equation. I have tried several different forms and always end up with the same answer: D = D. Which is accurate, but not a lot of help :). PLEASE HELP!!!

One last quick note: I am 37 years old and NOT in school. I am self teaching. In the past I've had experts hold back information in the spirit of not wanting to "help me cheat." I have been stuck on this problem for more than a month now due to the fact that none of the books I'm using have a worked out solution to this type of problem. It is not possible for you to help me cheat. You can only save my sanity by helping to end my frustration.:) Please give me as much detail as possible regarding this type of problem and how to properly set up a solution.

Thanks so much

Ernie


Answer
Hello Earnie,

Sorry to hear this problem, or ons like it, have been causing you so
much grief!  I hope I can help!

Looks like you are on the right path.
The key here is that distance=(rate)x(time) or D=RxT
Rearrange to get T=D/R (i.e. time = distance/rate)
The time to travel from home to the airport is: (150-D)/30 hrs
The time to travel from the airport to office is: D/60 hrs
Hence, the total time is the sum of those two, which we are
told is 3 hrs.  Thus, the equation you seek is:
(150-D)/30 + D/60 = 3

Multiplying by 60 on both sides (to simplify) yields:
2(150-D) + D = 180
300-2D+D=180
300-D=180
D=120

D=120 miles.

OK?  Was this helpful enough for you to feel confident in solving
other distance-rate-time problems???

TTYL, Abe

Algebra

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Abe Mantell

Expertise

Hello, I am a college professor of mathematics and regularly teach all levels from elementary mathematics through differential equations, and would be happy to assist anyone with such questions!

Experience

Over 15 years teaching at the college level.

Organizations
NCTM, NYSMATYC, AMATYC, MAA, NYSUT, AFT.

Education/Credentials
B.S. in Mathematics from Rensselaer Polytechnic Institute
M.S. (and A.B.D.) in Applied Mathematics from SUNY @ Stony Brook

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