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Algebra/trigonometry 1

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Expert: - 1/19/2009


Question

example diagram
oil flows in a pipeline of diameter 30cm to a depth of 12.05cm,as shown on a diagram above.calculate:
1.the cross sectional area of the oil.
2.the wetted perimeter of the pipe(that is the part of the pipe which is in contact with oil).
*these example the cross sectional area of the oil is the area of the sector.

Answer
1. If you draw lines from the center of the pipeline to the edges of the pipe at the top of the oil, you form a triangle with an angle at the center of 157.32 degrees.  The area of the circle with that central angle = (pi)(15^2)(157.32/360) = 308.9 cm^2.  Subtract the area of the triangle, 43.4 cm^2, and the cross sectional area of the oil is 308.9 cm^2.  
2. Perimeter = (pi)(30)(157.32/360) = 41.2 cm

Richard J. Raridon

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