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Algebra/Variation and problem solving

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Expert: - 11/17/2009


Question
Supose x varies directly with y and inversely with the sqare root of z. If x is 5/2 when y is 2 and z is 16, find y when x is 1/9 and z is 9.


Answer
It is said that x = Ay/√z.
Putting in x=5/2, y=2, and z=16 give us 5/2 = 2A*(1/√16) = 2A/4 = A/2.
Since 5/2 = A/2, it cam be computed that 5=A.

The equation is x = 5y/√z, so put in 1/9 for x and 9 for z.
It is known that √9 = 3, so we have 1/9 = 5y/3.

Multiply both sides by 3/5, and that gives y = 3/45 = 1/15.

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Scott A Wilson

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