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Question
I am supposed to use the quadratic formula to solve this equation:
x^2-5x= -10
To use the quadratic equation, put it in its proper form.
That would be x² - 5x + 10 = 0.
Thus, we have a=1, b=-5, and c=10.
The quadratic equation is (-b±√(b²-4ac))/(2a).
Using the data gives, that is (5±√(25-40))/2.
That is, (5±√-15)/2.
If you have gotten to complex numbers, the squareroot exists and is (5±√15•i)/2.
If your only dealing with real numbers, it has no factors.
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Answers by Expert:
Scott A Wilson
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Any algebraic question you've got, like linear, quadratic, exponential, etc.
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solving story problems
solving linear, parabolic, and 3rd order equations
solving equations with multiple variables
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documents at Boeing
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MS at math OSU in mathematics at OSU
BS at OSU in mathematical sciences (math, statistics, computer science)
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both BS and MS degrees were given with honors
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