Expert: Richard J. Raridon - 4/22/2009

Question
I do not know how to find the zero's of this function.

1/3x^3-x^2-3x+2

please help

Answer
For clarity you should write it (1/3)x^3-x^2-3x+2.  You can't factor it so write it f(x) = (1/3)x^3-x^2-3x+2
so that f(0) = 2 and f(1) = -5/3 so you know that one root has a value between 0 and 1.  You can narrow it down by calculating
f(0.1), f(0.3), etc.  
Also, f(4) = -122/3 and f(5) = 11/3 so there's another root between
4 and 5.  The third root is between -2 and -3.