Algebra/Algebra 2 Questions
Expert: Abe Mantell - 5/27/2009
QuestionHello!
Could you please help me with these problems? I have an idea of how to do these, but am not entirely sure that I am right. Any sort of help will be very much appreciated!
Thanks so very much!
Amanda
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1.) Solve for x: | x + 2 | = 8
6 only
-6, 10
No solution
6, -10
2.) Solve for x: | -3x - 6 | = 21
-9 only
-9, 5
9, -5
No solution
3.) Solve for x: | -2x - 3 | = -5
1 only
1, -4
No solution
-1, 4
4.) Solve | x - 4 | = | 5 - 2x |
1, 3
1 only
3, -3
-1, -3
5.) Solve for x: | -2x + 3 | = | x - 15 |
6, -6
6, -12
-6, 12
-6 only
6.) Solve for x: | 2x - 4 | + 3 = 5
3 only
-3 only
3, 1
3, -2
7.) Solve for x: | 5 - x | = | -x + 3 |
No solution
0, 4
-1, 1
4 only
8.) Solve for x: | x/3 - 4 | = 2/3
10, 14
6, 2
-10, -14
-6, -2
9.) Solve for x: | x/6 + 5 | + 1/3 = 3/4
0, -5
-25, -30
-55/2, -65/2
0, -9
AnswerHello Amanda,
Wow, you have many questions there...looks like a HW list!
How about I do 3 of them so you get the idea.
(Of course, you could simply just check each answer, but here is
how you do them...)
1.) Solve for x: | x + 2 | = 8
-- Either x+2=8 or -(x+2)=8
-- (since the absolute value will "get rid of" the negative sign...)
-- Thus, either x=6 or x=-10
4.) Solve | x - 4 | = | 5 - 2x |
-- Either x-4=5-2x or -(x-4)=5-2x
-- (the other two cases would be equivalent to one of these)
-- Thus, 3x=9 or -x+4=5-2x ==> x=3 or x=1
9.) Solve for x: | x/6 + 5 | + 1/3 = 3/4
-- | x/6 + 5 | = 3/4 - 1/3
==> Either x/6 + 5 = 5/12 or -(x/6 + 5) = 5/12
==> x/6 = 5/12 - 5 or -x/6 - 5 = 5/12
==> x=-55/2 or x=-65/2
I hope this enables you to finish the rest of them...OK?
Abe