Algebra/algebra

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Question
we are doing co-ordinates of the points on a line graph.I an a little confused. The question is
The points (1,3),(2,5),(8,17),(50<101),and (1000,2001) all lie on line M.
The points(1,1),(2,3),(8,negative15),(59,negative99)and(1000,negative1999)all lie on line N.
a.form the equations of both the lines.show you work
b.What are the co-ordinates of the point of intersetion of lines M and N?
c.write the co-ordinates of the intersections of lines M and N with x-axis.
d.Write the co-ordinates of the intersections of lines M and N the y- axis.
And she told me to use this formula for this problem (y-y1)=m(x-x1) and the x and the y are left as variables.Math is really hard for me.These are homework problems.

Answer
Hello Sabrina,

a) All we need are two points to determine a line.  Let's use the
- the first two: (1,3) & (2,5)...find the slope: m=(5-3)/(2-1)=2
- Now use the formula (y-y1)=m(x-x1) ==> y-3=2(x-1) ==> y-3=2x-2
- so the equation is: y=2x+1, and you can verify all the other points
- also check out.
- for the other line, let's use (1,1) & (2,3)...slope, m=(3-1)/(2-1)=2
- so y-1=2(x-1) ==> y-1=2x-2 ==> so the equation is y=2x-1

b) Set them "equal to each other" to determine where they intersect.
- thus 2x+1=2x-1 gives 1=-1, which is impossible, so they do not
- intersect (since they are parallel).

c) x-intercepts are where y=0...
- for M: 2x+1=0 ==> x=-1/2
- for N: 2x-1=0 ==> x=1/2

d) y-intercepts are where x=0...
- for M: y=+1
- for N: y=-1

I hope this helps!  Enjoy!!  :-)

Abe

Algebra

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Abe Mantell

Expertise

Hello, I am a college professor of mathematics and regularly teach all levels from elementary mathematics through differential equations, and would be happy to assist anyone with such questions!

Experience

Over 15 years teaching at the college level.

Organizations
NCTM, NYSMATYC, AMATYC, MAA, NYSUT, AFT.

Education/Credentials
B.S. in Mathematics from Rensselaer Polytechnic Institute
M.S. (and A.B.D.) in Applied Mathematics from SUNY @ Stony Brook

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