Expert: Scott A Wilson - 9/15/2009

Question
I need help with a few questions.

1. If c^2=d, then c is the (need to enter word) of d

2. another way to write sqrtA/B is....... (i think its sqrt(a*b) )

3.simplify. sqrt6y-1+3=9    (6y-1+3=9 is under the sqrt sign)

Please help!!! Thanks

Answer
1. c^2 is known c squared = c*c.
The oppositve of ^2 is ^(1/2), or the opposite of square is squareroot.
If c^2 = d, it can then be said that c squared is d, or c is the squareroot of d.
So c = d^(1/2) = d^0.5 = √d.

2. sqrt(A/B) = √(A/B) = √A/√B = (A/B)^0.5 = (A/B)^(1/2).

3. An equality sign can't be put under a squareroot.
I believe the problem is √(6y-1) + 3 = 9, or else -1+3 would have been done.
Subtracting 3 from both sides, we get √(6y-1) = 6.
Squaring a squareroot cancels both, so √(6y-1)² = 6² turns into 6y-1 = 36, or 6y = 37, or y=37/6,
or y = 6 1/6.