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Question
I am trying to calculate a complex numbers problem... I need to show that ((-1+sqrt(3)i)/2)^3 is equal to 1.  I'm not quite sure how to calculate this with the i.  

Answer
Hello Kristina,

So you have ((-1+sqrt(3)i)/2)^3

The first thing you should realize is that you can write this as

(a+bi)^3

You can convince yourself of this by substituting

a=-1/2

and

b=sqrt(3)/2

right?

So all you need to do is carry out the expansion of the binomial to the power of 3.

You'll get

(a+bi)^3 = a^3 + 3(a^2)(bi) + 3a(bi)^2 +(bi)^3

Now, it's important to remember that

i^2=-1, i^3=-i, i^4=1, etc.

so you can substitute these results into the equation above. After you've done that, all you need is to plug the numbers back in (a and b) and simplify. It should work out!

Hope this helps but let me know if you still have problems with it.

Cheers,
David  

Algebra

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