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Hi, I am trying to help tutor my son through his math class. Here is the question. If you can get me started I think it will come back to me.
Find a linear function with f(-1)=2 and f(3)=1.
How do I set this up?
The first point is (-1,2) and I will call it (x1,y1).
The second point is (3,1) and I will call it (x2,y2).
The slope m is (y2-y1)/(x2-x1) = (1-2)/(3-(-1)) = -1/4.
Take y-y1 = m(x-x1), put in what m, x1, and y1 are, and there's the answer.
This is in the point-slope form.
To put it in point-slope from, take y = mx - m(x1) + y1.
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| Rating(1-10) | Knowledgeability = 10 | Clarity of Response = 10 | Politeness = 10 |
| Comment | Thank you Scott! Yes, that makes great sense and is quite clear. Thank you for the quick response so we did not loose much time. A great service! *netta | ||
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Answers by Expert:
Scott A Wilson
Expertise
Any algebraic question you've got, like linear, quadratic, exponential, etc.
Experience
solving story problems
solving linear, parabolic, and 3rd order equations
solving equations with multiple variables
Publications
documents at Boeing
Education/Credentials
MS at math OSU in mathematics at OSU
BS at OSU in mathematical sciences (math, statistics, computer science)
Awards and Honors
both BS and MS degrees were given with honors
Past/Present Clients
students from all over since the 80's; over 1,000 in algebra
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