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Algebra/percentage of games
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Question
A team has won 71 games out of 116 played. If the team on average wins 3 games out of 4, how many games must be played to get the percentage of games won to 66.6666...% (2/3)?
We need the fraction of game to be 2/3. Currently it is 71/116.
I could do it by incrementing the number wond and looking at the percentage:
If the win 4 more, the percentage will be 5/8.
If they win 9 more, it will be 16/25.
If they win 19 more, it will be 90/135 = 18/27 = 2/3, and that's it.
What we need is (71+x)/(116+x) = 2/3, where x is an integer.
This means that 3(71+x) = 2(116+x) => 213 + 3x = 232 + 2x => 3x - 2x = 323 - 213 => x = 19.
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Algebra
Answers by Expert:
Scott A Wilson
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Any algebraic question you've got, like linear, quadratic, exponential, etc.
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MS at math OSU in mathematics at OSU
BS at OSU in mathematical sciences (math, statistics, computer science)
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