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Question
in the equation: ((2/2+h) -1)/ h
why is it that you can multiply the denominator by (2+h)/(2+h) in order to cancel (common denominators)? why does this work?
The fraction that is being looked at is [2/(2+h)]/h.
Multiplying the denominator h by (2+h)/(2+h) gives
[2/(2+h)]/[h(2+h)/(2+h)].
Since the numerator and the denominator of the fraction are both divided by (2+h), they can both be multiplied by (2+h), so (2+h) is cancelled out.
All that is left is 2/[h(2+h)].
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Algebra
Answers by Expert:
Scott A Wilson
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Any algebraic question you've got, like linear, quadratic, exponential, etc.
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solving story problems
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MS at math OSU in mathematics at OSU
BS at OSU in mathematical sciences (math, statistics, computer science)
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