Expert: Richard J. Raridon - 12/5/2010

Question
I'm in the 11th grade and i'm 16. I 'm trying to figure out
how to find the vertex, the axis of symmetry, the maximum or
minimum value, and the domain and the range of the functions:
y=-1.5(x+20)^2 and F(x)=-(x-4)^2-25

Answer
One standard equation for a parabola is (x-h)^2 = 4a(y-k)
So if you rearrange your equation to be (x+20)^2 = (-1/1.5)y
the vertex is at (h,k) which is (-20,0), the axis of symmetry is
x = -20 and the maximum value is 0.  I don't do domains and ranges.
For the other one, (x-4)^2 = F(x)-25
so the vertex is at 4,25, the axis of symmetry is x=4 and the minimum value is 25