You are here:

Algebra/equation with expalination

Advertisement


Question
the employees in a certain factory are divided into three wages classification. one group is paid at the rate of Rs. 25 per day , a second group in which there are twice as many employees as in the first group, is paid at the rate of rs. 40 per day and a third group , in which there are half as many employees as in the other two groups is paid Rs. 50 per day. if the total daily pay roll is Rs. 5400, how many employees are there in each group ?

Answer
Let there be n people in the 1st group, making 0.25 Rs/day.
This means that there are 2n in the 2nd group, making 0.4 Rs/day.
This means that there are n/2 people in the 3rd group, making 0.5 Rs/day.

The total wages would be n(0.25) + 2n(0.4) + 0.5n(0.5).
Multiply out the equation and get 0.25n + 0.8n + 0.25n.

Set this equal to 5,400 and solve for n.
The answer to what was given is not an integer, so make sure the values were input correctly.

Algebra

All Answers


Answers by Expert:


Ask Experts

Volunteer


Scott A Wilson

Expertise

Any algebraic question you've got, like linear, quadratic, exponential, etc.

Experience

solving story problems solving linear, parabolic, and 3rd order equations solving equations with multiple variables

Publications
documents at Boeing

Education/Credentials
MS at math OSU in mathematics at OSU BS at OSU in mathematical sciences (math, statistics, computer science)

Awards and Honors
both BS and MS degrees were given with honors

Past/Present Clients
students from all over since the 80's; over 1,000 in algebra

©2012 About.com, a part of The New York Times Company. All rights reserved.