Algebra/question
Expert: Scott A Wilson - 5/7/2010
QuestionDutch elm disease is a fungal disease that kills elm trees. It is spread by certain species of bark beetle. The disease was first reported in the United States in 1928, with the beetles believed to have arrived in a shipment of logs from the Netherlands destined for use as veneer in the Ohio furniture industry. The disease spread slowly from New England westward and southward, almost completely destroying the famous elms in the “Elm City” of New Haven, reaching the Detroit area in 1950, the Chicago area by 1960, and Minneapolis by 1970. (Source: Wikipedia)
Suppose a region has 8000 healthy elm trees. In 1950, bark beetles harboring the fungus arrive in the region. In each subsequent year, the number of elm trees that contract the disease is 20% of the number of healthy trees at the end of the previous year. Once a tree is infected, it stays infected.
(a) Find a difference equation describing the spread of Dutch elm disease through the region’s 8000 elm trees. Clearly define each variable.
(b) Use your difference equation to find the total number of infected elm trees for each of the first six years after the arrival of the beetles.
(c) Make a large, well-labeled graph showing the spread of Dutch elm disease, with total number of infected elm trees on the vertical axis and time in years on the horizontal axis. Number each axis appropriately. Include at least six years. Use graph paper or a computer program.
(d) Solve the difference equation.
(e) Use the solved difference equation to find the number of infected elm trees 20 years after the arrival of the beetles.
(f) Use the solved difference equation to find in what calendar year (like 1983) the number of infected elm trees will be 7560. You must solve the solved difference equation; you may not “guess and check”. Get an equation for n and solve it.
Answer(a) Since there are 8000 trees and 20% chance of being infected, the number of healthy trees would be 80% of the trees that were healthy the year before. Thus, the equation is
f(x) = 8000(1-0.8^x) where x is the years that have passed and f(x) is the number of sick trees.
As can be seen, after only 3 years almost half of the trees are infected.
(b)
0 8000
1 6400
2 5120
3 4096
4 3276.8
5 2621.44
Now these should really be in integers, so year 4 is 3277, which makes 5 into 2621.6,
which rounds up to 2622.
(c) Make a graph, with the x-axis as years and the y-axis as the number of trees.
(d) Already solved it.
(e) I did the first column by rounding each time and the second by using numbers past the decimal. As can be seen, there is little difference between them.
Year Uninfected Trees
1 0 0
2 1600 1600
3 2880 2880
4 3904 3904
5 4723 4723.20
6 5378 5378.56
7 5902 5902.85
8 6322 6322.28
9 6658 6657.82
10 6926 6926.26
11 7141 7141.01
12 7313 7312.81
13 7450 7450.24
14 7560 7560.20
15 7648 7648.16
16 7718 7718.53
17 7774 7774.82
18 7819 7819.86
19 7855 7855.88
20 7884 7884.71
(f) As can be seen, 7560 is in the column above; the year is the number of the left.