You are here:

Algebra/i need help

Advertisement


Question
Twice one number is 20 more than a second number. One-fourth of the first number is 2 less than 0.25 of the second. Find each number.

Answer
Call the two numbers s and t.
The 1st statement says that 2s = t + 20.
The 2nd statements says that s/4 = t/4 - 2.
Multiplying the 2nd equation by 8 gives 2s = 2t - 16.

Since 2s = t + 20 and 2s = 2t - 16, solve t + 20 = 2t - 16 for t.
Put this in one equation and solve for s.
Put both values in the other equation to make sure the answer is correct.

Hint: both numbers are divisible by 4.  

Algebra

All Answers


Answers by Expert:


Ask Experts

Volunteer


Scott A Wilson

Expertise

Any algebraic question you've got, like linear, quadratic, exponential, etc.

Experience

solving story problems solving linear, parabolic, and 3rd order equations solving equations with multiple variables

Publications
documents at Boeing

Education/Credentials
MS at math OSU in mathematics at OSU BS at OSU in mathematical sciences (math, statistics, computer science)

Awards and Honors
both BS and MS degrees were given with honors

Past/Present Clients
students from all over since the 80's; over 1,000 in algebra

©2012 About.com, a part of The New York Times Company. All rights reserved.