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Question
if I have the problem 7! / {2!*(3+4)!}   , how do I simplify or solve it?

Answer
Now it could be said that 2! = 2, 3! = 3*2! = 6, 4! = 4*3!=24, 5! = 5*4! = 120,
6! = 6*5!= 720, and 7! = 7*6! = 5040, but we don't need to do this.

When doing any math problem, simplify that simple expressions firts.
It is known that 3+4=7, so we have 7!/(2!*7!).

Since 7! appears in the numerator and the denominator, we don't really care what it is,
for we can divide both the numerator and the denominator by 7!.

This gives 1/2!.  Given what 2! was above, that can be computed.

By the way, I like the use of { ( ) }, even though ( ( ) ) is understandable, for it is simpler to read with no chance of error.

Algebra

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Scott A Wilson

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