Expert: Richard J. Raridon - 8/4/2010

Question
Im dina, help me please?!
Simplify.

d^2 d^4

m^-2 n^0

(4a^2b)^3 (ab)^2

(3a^3)^2 / 18a

(xz/y)^6

(w^2 z^4)^3 / (-wz^5)^2 ( w^4 z^2)

Square root of 1/2

3 square root of 5 + 2 square of 5

Square root of 98 + square root of 50 - square root of 5

4 square root of 6 • 5 square root of 2

Answer
d^6
1/m^2
64a^4b
a^5/2
x^6z^6/y^6
If you meant all that in the denominator you should have written it
(w^2z^4)^3/[(-wz^5)^2(w^4z^2)] = 1
you can write square root (1/2)^1/2 = (2^1/2)/2
5(5^1/2)
7(2^1/2) +5(2^1/2) -(5^1/2) = 12(2^1/2) -(5^1/2)
DO NOT USE a dot or x to indicate multiplication
4(6^1/2)(5)(2^1/2) = 40(3^1/2)