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Algebra/Solving Problems Using Equations

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Expert: - 11/6/2011


Question
The sum of the smaller of two consecutive integers and twice the larger integer is 47. What are the integers?

Answer
The smaller is x, so the larger is x+1.
The sum of the smaller and twice the larger is x + 2(x+1) = 3x + 2.
Since we are given that 3x + 2 = 47, this can be converted to 3x = 45.
From that, we can say that x = 15, so the next number, x+1, is 16.

Checking this out, 15 + 2(16) = 15 + 32 = 47.

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Scott A Wilson

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