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Question
The perimeter of a NBA-sized basketball court is 288 ft. The length is 44 ft longer than the width. Find the dimensions of the court.
The court has a length that is 44' longer that the width, so L = W + 44.
The perimeter is twice the length plus twice the width, so P = 2W + 2L.
The perimeter is 288, we have 288 = 2W + 2L.
Dividing this equation by 2 gives 144 = W + L.
Since L is 44 over W, it can be seen that L = 50+44 = 94 and W=50.
Checking, the total perimeter is 188 + 100 = 288,
and 94 is 44 greater than 50.
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Answers by Expert:
Scott A Wilson
Expertise
Any algebraic question you've got, like linear, quadratic, exponential, etc.
Experience
solving story problems
solving linear, parabolic, and 3rd order equations
solving equations with multiple variables
Publications
documents at Boeing
Education/Credentials
MS at math OSU in mathematics at OSU
BS at OSU in mathematical sciences (math, statistics, computer science)
Awards and Honors
both BS and MS degrees were given with honors
Past/Present Clients
students from all over since the 80's; over 1,000 in algebra
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