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Algebra/Algebra 2, Circles
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Question
Can you please show work calculating the equation of the circle that is center on line x + y = 4; tangent to both first quadrant coordinate axes?
For the circle to have a center on the line x+y=4 and be tangent to both the x and y axis,
the center needs to be where x and y are equal, and that is x=y=2.
Since the distance away from the axis is both 2, it would have radius 2.
Thus, the equation is (x-2)² + (y-2)² = 2², and 2² is 4.
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| Rating(1-10) | Knowledgeability = 10 | Clarity of Response = 10 | Politeness = 10 |
| Comment | Thank you soo much. You cannot believe how many sketches I went through. I missed the very premise of the problem, looking at where the x and y are both equal! Such a great help!! | ||
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Scott A Wilson
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