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Question
Hi! My maths is not terrific and I'm having a bit of trouble understanding how an equation that has already been worked gets from one stage to the other. The first stage is:
(2x)^2/(1.000 - x)(2.000 - x) = 50.5
I don't quite get how they turn it into:
4x^2 = 50.5(x^2 - 3.000x + 2.000)
and then into:
46.5x^2 - 151.5x + 101.0 = 0
Sorry for the long question!
Thanks for your help,
Erin

Answer
Hello Erin,

The equation is best written:
(2x)^2/((1.000 - x)(2.000 - x)) = 50.5
now multiply both sides by (1.000 - x)(2.000 - x) to get
(2x)^2=50.5(1.000 - x)(2.000 - x), now expand the product (1.000 - x)(2.000 - x)
4x^2=50.5(2.000-2.000x-1.000x+x^2)
4x^2=50.5(2.000-3.000x+x^2), now distribute the 50.5
4x^2=101.0-151.5x+50.5x^2, now subtract 4x^2 from both sides
0=101.0-151.5x+46.5x^2

OK, do you see it now?  Let me know if you have any other questions.

Abe

Algebra

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Abe Mantell

Expertise

Hello, I am a college professor of mathematics and regularly teach all levels from elementary mathematics through differential equations, and would be happy to assist anyone with such questions!

Experience

Over 15 years teaching at the college level.

Organizations
NCTM, NYSMATYC, AMATYC, MAA, NYSUT, AFT.

Education/Credentials
B.S. in Mathematics from Rensselaer Polytechnic Institute
M.S. (and A.B.D.) in Applied Mathematics from SUNY @ Stony Brook

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