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Algebra/More on dot product..

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Question
I just want to thankyou for your previous response to my question.

My question is as follows: If A.B = A.C then does B=C ? I can easily just let A = (0,1,0), B = (1,0,0) and C= (0,0,1) which means that A.B = A.C = 0 and shows that B (does not equal) C. Is there a more valid way to show this?

The question does lead on to say: Show with a sketch what is the condition that the three vectors satisfy. I don't understand what the question is asking me to prove here. Thank you in advance!

Answer
Hello Jay,

Your example is definitely enough to prove what you want to but yes, there should be a, not more VALID, but more GENERAL way to do it. Try writing the condition A.B=A.C without putting any numbers, for example: A=(a1,a2,a3), B=(b1,b2,b3), etc. and see where this gets you. You may also want to try it using the other form of the dot product: A.B=|A||B|cos(angleAB).

I think what the second part is asking is that you write down (and draw) what vectors A,B and C must satisfy so that (A.B=A.C).

Hope this helps,
David  

Algebra

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David Montiel

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