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Question
45-[4-2y-4(y+7)] = -4(1+3y)-[4-3(y+2)-2(2y-5)] having trouble getting the answer to this problem.
Eliminate the innermost (round) brackets first
45-[4-2y-4(y+7)] = -4(1+3y)-[4-3(y+2)-2(2y-5)] =
45-[4-2y-4y-28] = -4-12y-[4-3y-6-4y+10] =
45-[-6y-24]=-4-12y-[-7y+8] =
now eliminate the square brackets
45+6y+24 = -4-12y+7y-8
bring y terms to the left and everything else to the right
6y+12y-7y = -4-8-45-24
combine like terms
11y = -81
y = -11/81
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Algebra
Answers by Expert:
Socrates
Expertise
Any questions on High School Algebra, College Algebra, Abstract Algebra. I can help with word problems, solving equations, trigonometry, inequalities, Gaussian Elimination, Linear Algebra, groups, fields, you name it!
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Ph.D. in Mathematics, specialist in Algebra. I have taught High School students and college students at three state universities.
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Mathematical Association of America. American Mathematical Society.
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Regular contributions to the problems section of the American Mathematical Monthly journal.
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B.S., M.S., Ph.D.
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