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Divide:

a. x^2+6x+8/x+4

b. 4x^2+5x-9/x-2

I have tried everything to figure these problems out. If you could help I would appreciate it.

Age: 44

Grade level-second year college

Did you ever learn to factor an equation such as x^2+6x+8? It's going to have two factors,

(ax+b) and (cx+d). If you multiply those together you get acx^2 +(ad+bc)x +bd.

If you compare that to your equation, you will see that a and c each has to be 1 and bd = 8.

Therefore, b+d = 6 and since bd=8, b and d have to be 2 and 4.

Thus, x^2+6x+8 = (x+2)(x+4) and if you divide by x+4 you get x+2.

b. You can factor 4x^2+5x-9 into (4x+9) and (x-1) but that doesn't help you this time since one of the factors is not x-2.

If you divide, like long division, you get 4x+13 with 17 left over.

Algebra

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