You are here:

# Algebra/Algebra 1

Question
Divide:

a. x^2+6x+8/x+4

b. 4x^2+5x-9/x-2

a. Note that x^2 + 6x + 8 = (x+4)(x+2); dividing by x+4 cancels them, leaving x+2.

b. Take 4x^2 + 5x - 9 = (x-2)(4x+C).  Multiplying out gives 4x^2 + (C-8)x - 2C.
This doesn't look promising, so try division.

Multiply x-2 by 4x and get 4x^2-8x.  Subtracting off from 4x^2 + 5x - 9 cancels the 4x^2,
and 5x - -8x = 13x, so the result is 13x - 9.

Multiplying x-2 by 13 gives 13x - 26.  Subtracting this from 13x - 9 cancels the 13x terms.
This leaves -9 - -26 = 17.

From this, the result is (4x+13), remainder 17.

Note that (x-2)(4x+13) = 4x^2 + 5x - 26, and the difference is 17, so that is the remainder.

Algebra

Volunteer

#### Scott A Wilson

##### Expertise

Any algebraic question you've got. That includes question that are linear, quadratic, exponential, etc.

##### Experience

I have solved story problems, linear equations, parabolic equations. I have also solved some 3rd order equations and equations with multiple variables.

Publications
Documents at Boeing in assistance on the manufacturiing floor.

Education/Credentials
MS at math OSU in mathematics at OSU, 1986. BS at OSU in mathematical sciences (math, statistics, computer science), 1984.

Awards and Honors
Both my BS and MS degrees were given with honors.

Past/Present Clients
Students in a wide variety of areas since the 80's; over 1,000 of them have been in algebra.