Simplify the expression.Assume that variable represent non-negative real numbers.

a. x^11/6

b. 49-^3/2


Note that in mathematics, exponent are done before division.

Since I believe this is not the case in this problem,
(a) could be written as [x^(11/6)]/[x^(11/12)].

When two numbers are divided by each other, the exponents are subtracted.
Since that gives us x^(11/6 - 11/12), it can be seen the exponent needs a common denominator.
If 11/6 is multiplied by 2/2, that gives 11/12.  Since both fractions now have the same denominator, the difference can be taken.  With 22/12 - 11/12, it is known that 22 - 11 = 11, so we have 11/12.  Thus said, it can be seen the answer is x^(11/12).

b. Again, as written, the problem would be 1/[(49^3)*2].
That is, 1/(49*49*49*2) = 2401*98 = 139,398.

I believe again this problem should really be 49^(-3/2) = 1/49^(3/2).
Since 49^(1/2) = 7, this is the same as 1/7^3.
Since 7^3 = 343, this is 1/343.


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Scott A Wilson


Any algebraic question you've got. That includes question that are linear, quadratic, exponential, etc.


I have solved story problems, linear equations, parabolic equations. I have also solved some 3rd order equations and equations with multiple variables.

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