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Solve the system:

y = x^2 + 5x + 4

y = 8x + 8

Thank you very much for your time and assistance!

Take y = 8x + 8 and put into the 1st question.

This gives 8x + 8 = x² + 5x + 4.

Subtracting 8x + 8 from both sides gives 0 = x² - 3x - 4.

The quadratic equation has the square-root of (9-12) = sqrt(-3) in it.

The complete answer is x = (3ħsqrt(-3))/2.

Put that in y = 8x + 8 to get y.

That gives two possible choices for y, since the plus or minus gives two choices for x.

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